Question

sulfuric acid (a newtonian fluid) with a density of 1980 kg/m3 and a viscosity of 26.7 cp is flowing in a 35-mm-diameter pipe. if the acid flow rate is 1 m3/min, what is the pressure drop (i.e., pressure differential) from major frictional losses for a 30-m length of smooth pipe? (1 cp

Answer 1

The pressure drop in the pipe is approximately 36,528.76 N/m².

Step-by-step explanation:

In order to calculate the pressure drop, we can use the Hagen-Poiseuille equation:

ΔP = (128 × μ × L × Q) / (π × d4)

where ΔP is the pressure drop, μ is the viscosity, L is the length of the pipe, Q is the flow rate, and d is the diameter of the pipe.

Plugging in the values given in the question, we get:

ΔP = (128 × 26.7 cp × 30 m × 1 m3/min) / (π × (35 mm / 1000) m3)

Simplifying the equation, we find that the pressure drop is approximately 36,528.76 N/m2.