Question

using an overflow rate of 26.0 m/d and a detention time of 2.0 h, size a primary sedimentation tank for the average flow at cynusoidal city (problem 8-1). what would the overflow rate be for the unequalized maximum flow? assume 15 sedimentation tanks with length-to-width ratio of 4.7.

Answer 1

To size a primary sedimentation tank for the average flow at Cynusoidal city, we can calculate the tank area using the overflow rate and detention time. The tank area is found to be 312 m². The overflow rate for the unequalized maximum flow is calculated to be 1.733 m/d.

To size a primary sedimentation tank for the average flow at Cynusoidal city, we can use the equation: Q = A*V

Where Q is the flow rate, A is the tank area, and V is the overflow rate.

Given the overflow rate of 26.0 m/d and the detention time of 2.0 h, we can calculate the tank area:

A = Q / V = (Q / T) * 24

Substituting the values, A = (26.0 m/d / 2.0 h) * 24 = 312 m²

Now, to calculate the overflow rate for the unequalized maximum flow, we need to consider the maximum flow rate. Assuming the maximum flow rate occurs when all the tanks are used, we need to divide the average flow by the number of tanks: max_flow = average_flow / number_of_tanks = 26.0 m/d / 15 = 1.733 m/d

So, the overflow rate for the unequalized maximum flow would be 1.733 m/d.