The equation of the line that passes through the point (−6,−5) and has a slope of 3/2 is y = 3/2x - 2.
We can use the point-slope form of the equation of a line, which is:
y - y1 = m(x - x1)
where:
y is the y-coordinate of any point on the line
y1 is the y-coordinate of the point (−6,−5)
m is the slope of the line
x is the x-coordinate of any point on the line
x1 is the x-coordinate of the point (−6,−5)
Plugging in the values we know, we get:
y - (-5) = (3/2)(x - (-6))
y + 5 = (3/2)
x + y = (3/2)x + 4
Therefore, the equation of the line that passes through the point (−6,−5) and has a slope of 3/2 is y = 3/2x + 4.
So the answer is B.