Question

What mass of sucrose, C₁₂H₂₂O₁₁, would be needed to prepare 100. mL of 0.13 M C₁₂H₂₂O₁₁?

Answer 1

To prepare 100 mL of 0.13 M C₁₂H₂₂O₁₁ solution, approximately 4.452 grams of sucrose would be needed.

Step-by-step explanation:

To calculate the mass of sucrose needed to prepare a 0.13 M solution, we need to use the formula:

moles of solute = molarity x volume (in L)

First, we need to convert the volume given in mL to L:

100 mL = 100/1000

= 0.1 L

Now, we can use the formula:

moles of sucrose = 0.13 M x 0.1 L

= 0.013 moles

To calculate the mass, we can use the formula:

mass = moles x molar mass

The molar mass of sucrose (C₁₂H₂₂O₁₁) is 342.3 g/mol.

mass = 0.013 moles x 342.3 g/mol

= 4.452 g

Therefore, you would need approximately 4.452 grams of sucrose to prepare 100 mL of 0.13 M C₁₂H₂₂O₁₁ solution.