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A rectangular floor frame is 32' x 52'.
How many 2x6–16' sills would be needed?

User Capkutay
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Final answer:

To create the sill for a rectangular floor frame measuring 32' x 52', the perimeter is 168 feet, and we would need 11 pieces of 2x6–16' sills when rounded up from 10.5.

Step-by-step explanation:

The student's question involves determining the quantity of 2x6–16' sills needed for a rectangular floor frame that measures 32' x 52'. To solve this, we need to calculate the perimeter of the floor frame and then determine how many 16-foot lengths of sill are required to cover this perimeter. Since the floor frame is rectangular, the perimeter can be calculated by adding twice the length to twice the width: (2 x 32') + (2 x 52') = 64' + 104' = 168'. Now, to find out how many 16-foot sills are needed, we divide the total perimeter by the length of each sill: 168' ÷ 16' = 10.5. Since we cannot have a half sill, we would need to round up, which means 11 sills would be required to go around the floor frame.

User JonatanE
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