Final answer:
The mass of carbon in 1 liter of the methane and butane mixture is 0.747 g.
Step-by-step explanation:
To find the mass of carbon in 1 liter of the methane and butane mixture, we need to calculate the mass ratio of carbon in each compound and then multiply it by the total mass of the mixture.
Methane (CH4) has a molar mass of 16 g/mol and one carbon atom, so the mass ratio of carbon in methane is 12 g/mol.
Butane (C4H10) has a molar mass of 58 g/mol and four carbon atoms, so the mass ratio of carbon in butane is 48 g/mol.
Since the density of the mixture is given as 1.895 g/L, the total mass of the mixture in 1 liter would be 1.895 g.
To calculate the mass of carbon, we need to calculate the fraction of the mixture that is methane and butane. Assuming ideal behavior, the molar fraction of methane is (mass of methane)/(molar mass of methane x density of the mixture), and the molar fraction of butane is (mass of butane)/(molar mass of butane x density of the mixture).
Using these fractions, the mass of carbon in the mixture can be calculated as (molar fraction of methane x mass ratio of carbon in methane) + (molar fraction of butane x mass ratio of carbon in butane).
Substituting the values into the equation, the mass of carbon in 1 liter of the mixture is:
Mass of carbon = (0.668 g/L x (12 g/mol))/(16 g/mol) + (1.227 g/L x (48 g/mol))/(58 g/mol)
= 0.747 g