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A box has 5 red balls and N blue balls. Two of the balls are randomly chosen. The probability that they are the same color is 11/21. Find the sum of all possible values of N___

User EAzevedo
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Final answer:

To find the sum of all possible values of N, the probabilities for both balls being red or blue are calculated and set equal to the given total probability of 11/21. After solving, the possible values for N are found to be 4 or 16, hence the sum is 20.

Step-by-step explanation:

The student is asked to find the sum of all possible values of N, given that the probability of selecting two balls of the same color from a box containing 5 red balls and N blue balls is 11/21.

Calculating the Probability

There are two scenarios where the two balls selected can be of the same color: both are red or both are blue. We start by calculating the probability for each scenario separately.

For both balls being red, the probability is:

P(Red and Red) = (5/5+N) * (4/4+N)

For both balls being blue, the probability is:

P(Blue and Blue) = (N/5+N) * ((N-1)/4+N)

Since the total probability of selecting two balls of the same color is given to be 11/21, we set up the equation:

(5/5+N) * (4/4+N) + (N/5+N) * ((N-1)/4+N) = 11/21

After solving for N, we find that N can be 4 or 16. Therefore, the sum of all possible values of N is 4 + 16 = 20.

User Rolevax
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