Question

A train is travelling at 15 m/s. It accelerates at 3 m/s² for 20 seconds. How far does the train travel in this time? (Hint: the equation for for uniform acceleration is v2 – u2 = 2as)

Answer 1

The question is about calculating the distance a train travels while it is accelerating. Using the kinematic equation s = ut + ½at², the train is found to travel 900 meters in the given time.

Step-by-step explanation:

The subject of this question is Physics, specifically dealing with kinematics which involves the calculation of distance traveled by an object with uniform acceleration.

The train initially travels at 15 m/s and accelerates at 3 m/s² for 20 seconds. To find the total distance covered, we can use the kinematic equation s = ut + ½at², where:

• u is the initial velocity,
• a is the acceleration,
• t is the time,
• s is the distance traveled.

Plugging the given values into the equation:

s = (15 m/s × 20 s) + ½(3 m/s² × (20 s)²)

s = (300 m) + (0.5 × 3 m/s² × 400 s²)

s = 300 m + 600 m

s = 900 m

So, the train travels 900 meters in that time period.