Question

A stationary block of 10.0 kg on horizontal surface is pulled by a horizontal rope. The coefficient of static friction μₛ​ is 0.70 and coefficient of kinetic friction μₖ

is 0.40 . Include a free body diagram for each part: a,b, and c. a. Suppose the tension in the rope is 50.0 N. Will the block begin to move?

Answer 1

(a) The free body diagram is shown in the image attached.

(b) The minimum force required to move the block is less than the tension applied on the block, so the block will not move.

How to calculate the minimum force required for the block to move?

The minimum force required for the block to move is calculated by applying the following formula as shown below;

Fs = μmg

where;

• μ is the coefficient of static friction
• m is the mass of the block
• g is acceleration due to gravity

The given parameters include;

mass of the block, m = 10 kg

coefficient of static friction = 0.7

The minimum force required for the block to move is calculated as;

Fs = 0.7 x 10 kg x 9.8 m/s²

Fs = 68.6 N

Since the minimum force required to move the block is less than the tension applied on the block, the block will not move.