Final answer:
These physics problems involve applying conservation of momentum and impulse-momentum theorem to determine velocities, momenta, and forces during and after collisions.
Step-by-step explanation:
The questions you've asked relate to the conservation of momentum, impulse, and types of collisions in classical mechanics, which are key concepts in physics. In general:
The momentum of an object is the product of its mass and velocity.
Impulse is the change in momentum of an object when a force is applied over a time interval.
An elastic collision is one where both momentum and kinetic energy are conserved.
An inelastic collision is one where momentum is conserved but kinetic energy is not necessarily conserved.
For your specific questions, you'll need to apply the conservation of momentum to solve for the velocities and the momentum before and after the collisions. Then, use the impulse-momentum theorem to determine the impulse and the forces involved based on the given times of contact.
Your complete question us: The same bullet from question 4 is fired horizontally. a. What is the momentum of the bullet just after being fired? b. In the distance are two blocks of wood each with a mass of 1.50 kg separated by 8 m so what is the total momentum of the system just after being fired now? c. The bullet strikes the first block and goes through the block. Both the block and the bullet move in the same direction the bullet was initially traveling. If the bullet carries on with a new velocity of 209.6
s
m
what is the bullets new momentum? What is the block's new momentum and the block's velocity? What type of collision is this? d. Now the bullet strikes the 2
nd
block and does not penetrate the block but sticks in it. What is the velocity of bullet/block combination? What type of collision is this? e. What is the momentum of the bullet/block combination? f. If the bullet is in contact with block 1 for 0.001 seconds what is the impulse felt by the bullet and block 1 ? g. What is the force felt by block 1 and the bullet? h. If the bullet came to rest in block two in 0.0005sec what was the impulse felt by the bullet and block 2 ? 4. Work-Energy Theorem and conservation of Energy: A bullet that has a mass of 100 g is fired straight up from a gun with a velocity of 2000
s
ft
from the top of a 150 m cliff. a. What is the kinetic energy of the bullet just after it was fired? b. What is the total potential energy of the bullet just before it was fired? c. How much work was done to get the bullet moving 2000
s
ft
assuming that it started at rest? d. How much work was done by the air to decrease the bullets speed to 1700
s
ft
? e. Assuming no air resistance, how high would the bullet go relative to the ground below the cliff? f. What would be the speed of the bullet as it hits the ground at the bottom of the cliff? 5. Momentum: The same bullet from question 4 is fired horizontally. a. What is the momentum of the bullet just after being fired? b. In the distance are two blocks of wood each with a mass of 1.50 kg separated by 8 m so what is the total momentum of the system just after being fired now? c. The bullet strikes the first block and goes through the block. Both the block and the bullet move in the same direction the bullet was initially traveling. If the bullet carries on with a new velocity of 209.6
s
m
what is the bullets new momentum? What is the block's new momentum and the block's velocity? What type of collision is this? d. Now the bullet strikes the 2
nd
block and does not penetrate the block but sticks in it. What is the velocity of bullet/block combination? What type of collision is this? e. What is the momentum of the bullet/block combination? f. If the bullet is in contact with block 1 for 0.001 seconds what is the impulse felt