Question

​​​​​​​In an electric motor, a rectangular coil WXYZ has 20 turns and is in a uniform magnetic field of 0.83 T. XY = 0.17 m, and WX = 0.11 m. Current in the coil is 4.5 A. Determine the maximum torque provided by the motor.

Answer 1

The maximum torque provided by the electric motor with a rectangular coil of 20 turns, 0.17 m by 0.11 m dimensions, carrying a current of 4.5 A in a 0.83 T magnetic field is 14.031 N·m.

Step-by-step explanation:

To determine the maximum torque provided by the electric motor, we need to use the formula for torque in a magnetic field, τ = nIBA cos(θ). For the maximum torque, the angle θ between the magnetic field and the normal to the plane of the coil is 90 degrees (cos 90° = 1). Given that the rectangular coil WXYZ has 20 turns (n = 20), carries a current of 4.5 A (I = 4.5 A), and is in a uniform magnetic field of 0.83 T (B = 0.83 T), and the dimensions of the coil are XY = 0.17 m and WX = 0.11 m. The area of coil A is found by multiplying these two dimensions (A = XY × WX). The area A = 0.17 m × 0.11 m = 0.0187 m². Plugging these values into the torque formula, we get τ = 20 × 4.5 A × 0.83 T × 0.0187 m² τ = 14.031 N·m. Hence, the maximum torque provided by the motor is 14.031 N·m.