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A ball thrown vertically upward is caught by the thrower after 3.00 s at the same height of the initial point of release. Find the maximum height the ball reaches from the point of release.

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Final answer:

The maximum height the ball reaches from the point of release is 21.15 m.

Step-by-step explanation:

To find the maximum height the ball reaches, we can use the equations of motion. Since the ball is caught at the same height as its initial release point, the displacement in the vertical direction is zero. Using the equation for displacement, 's = ut + (1/2)at^2', and taking upward motion as positive, the equation becomes '0 = u(3) + (1/2)(-9.8)(3)^2'. Solving for u, the initial upward velocity, we get u = 14.1 m/s. To find the maximum height, we can use the equation for displacement, 's = ut + (1/2)at^2', and solve for s. Plugging in the values, we have s = (14.1)(3) + (1/2)(-9.8)(3)^2 = 21.15 m.

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