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A flat sheet of ice (n=1.309) has a thickness of 1.9 cm. It is on top of a flat sheet of crystalline quartz (n=1.544) that has a thickness of 0.88 cm. Light strikes the ice perpendicularly and travels through it and then through the quartz. In the time it takes the light to travel through the two sheetshow far (in cm ) would it have traveled in a vacuum?

User Shahzeb
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Final answer:

The distance light would have traveled in a vacuum can be calculated by determining the time it takes for light to travel through the ice and quartz and then converting that time into the equivalent distance in a vacuum.

Step-by-step explanation:

To find out how far light would have traveled in a vacuum in the time that it takes to travel through a flat sheet of ice and a flat sheet of crystalline quartz, we need to calculate the time taken for the light to pass through each material and then determine the equivalent distance in a vacuum.

The speed of light in a medium is given by c/n, where c is the speed of light in a vacuum and n is the refractive index of the medium.

For ice, with n = 1.309, the speed of light is c/1.309. The time taken to cross 1.9 cm is therefore thickness/speed = 1.9 cm / (c/1.309).

Similarly, for crystalline quartz, with n = 1.544, the speed of light is c/1.544. The time taken to cross 0.88 cm is 0.88 cm / (c/1.544).

The total distance light would have traveled in a vacuum is the sum of the distances covered in ice and quartz, calculated using their respective times. This is equivalent to c multiplied by the total time (the sum of the individual times for ice and quartz).

User Shimanski Artem
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