Final answer:
The wavelength of the photon with an energy of 4.52×10-20 J is approximately 441 nm (4.41×10-7 meters), and the frequency is about 6.80×1014 Hz, calculated using the energy of a photon formula E = hc / λ.
Step-by-step explanation:
To calculate the wavelength λ and the frequency f of the photons with an energy of Ephoton = 4.52×10-20J, we use the formula E = hf = hc / λ, where h is Planck's constant and c is the speed of light. Given that the speed of light c is 3.00×108 m/s and Planck's constant h is 6.626×10-34 J×s, we can rearrange the formula to solve for the wavelength λ and frequency f.
First, we solve for the wavelength by rearranging the formula to λ = hc / E: λ = (6.626×10-34 J×s × 3.00×108 m/s) / (4.52×10-20 J) = 4.41×10-7 meters or 441 nm.
Next, to find the frequency f, we use the relationship c = fλ. The frequency f can be found by f = c / λ: f = 3.00×108 m/s / 4.41×10-7 meters = 6.80×1014 Hz.
Therefore, the wavelength of the photon is approximately 441 nm, and its frequency is approximately 6.80×1014 Hz.