Question

Billiard ball A of mass mₐ =0.123 kg moving with speed vₐ =2.80 m/s strikes ball B, initially at rest, of mass mᵦ=0.142 kg. As a result of the collision, ball A is deflected off at an angle of θₐ′=30.0 with a speed vₐ′=2.10 m/s, and ball B moves with a speed vᵦ​ at an angle of θᵦ to original direction of motion of ball A.

Answer 1

This question involves applying principles of conservation of momentum and kinetic energy to determine the outcomes of a collision between two billiard balls. It's a physics problem that requires breaking down velocities into components and using vector mathematics.

Step-by-step explanation:

The student's question is about a collision between two billiard balls, one of which is initially at rest. The problem involves concepts from physics, specifically in the topic area of mechanics, dealing with the conservation of linear momentum and kinetic energy in collisions.

To solve this problem, one must apply conservation laws and the equations derived from them to calculate the final velocity and trajectory of the two billiard balls post-collision. The key to solving such problems is to consider both the conservation of linear momentum and kinetic energy (in the case of perfectly elastic collisions), and to break down velocities into vector components when angles are involved.