Question

A square current loop carries a current 5 A. Each side of the square has a length 11 cm. The current loop is placed in a region of constant magnetic field. The field lines are perpendicular to the plane of the loop. What is the total force on the loop?

Answer 1

The total force on the square current loop can be determined using the equation F = (I * L)(B * sinθ), where F is the force, I is the current, L is the length of each side of the square loop, B is the magnetic field strength, and θ is the angle between the magnetic field and the plane of the loop.

Step-by-step explanation:

The total force on the square current loop can be determined using the equation F = (I * L)(B * sinθ), where F is the force, I is the current, L is the length of each side of the square loop, B is the magnetic field strength, and θ is the angle between the magnetic field and the plane of the loop.

In this case, the current is 5 A and each side of the square has a length of 11 cm. Since the magnetic field lines are perpendicular to the loop, the angle θ is 90 degrees.

Therefore, the total force on the loop is given by F = (5 * 11)(B * sin90) = 55B N, where B is the magnetic field strength in teslas.