Question

A solid ball of mass 1.60kg and diameter 11.0cm is rotating about its center of mass at 80.0rev/min. What is its kinetic energy ? 6.794×10-2 J You are correct. Your receipt no. is 160-3552 Help: Receipt Previous Tries If an additional 2.00J of energy are supplied to the rotational energy, what is the new angular speed of the ball in radians/sec?

Answer 1

To find the new angular speed of the ball, we can use the equation for rotational kinetic energy and rearrange it to solve for angular speed.

Step-by-step explanation:

When an additional 2.00J of energy is supplied to the rotational energy of the ball, its new angular speed can be found using the equation for rotational kinetic energy:

KErot = 0.5 * I * ω^2

Given that the initial kinetic energy of the ball is 29.6 J, we can rearrange the equation to solve for the new angular speed:

ω^2 = (2 * KErot) / I

Substituting the values into the equation, we get:

ω^2 = (2 * 31.6 J) / (0.5 * 2.34 kg.m^2)

ω^2 = 2.70 rad/s

Taking the square root of both sides, we find that the new angular speed of the ball is approximately 1.64 rad/s.