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During a camera fash, 2.98×10¹⁷electrons travel through a conductor very quickly, taking 3.3 ms to travel from one side of the conductor to the other side. What is the current, in Amps, for this wire?

User Sanaulla
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Final answer:

The question involves calculating the current induced by a known number of electrons traveling through a conductor over a specific time period, with the intent to find the current in Amps.

Step-by-step explanation:

The question pertains to the calculation of current in a conductor when a known quantity of electrons moves through it during a given time interval. To find the current (I), one needs to know the charge (Q) transferred and the time (t) this transfer takes. The charge of a single electron is approximately 1.602 × 10⁻¹¹ coulombs (C). Therefore, the total charge Q transported by 2.98 × 10¹⁷ electrons is calculated as:

Q = number of electrons × charge per electron
Q = 2.98 × 10¹⁷ × 1.602 × 10⁻¹¹ C

To find current: I = Q / t
Converting milliseconds to seconds: 3.3 ms = 3.3 × 10⁻³ s

The question is looking to find the current in Amps passing through the wire when 2.98 × 10¹⁷ electrons have traveled across in 3.3 ms.

User Dinvlad
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