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A generator rotates at 85 Hz in a magnetic field of 0.030T. It has 850 turns and produces an rms voltage of 130 V and an rms current of 35.0 A. What is the peak current produced?

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Final answer:

The peak current produced by the generator is approximately 49.5 A, calculated using the formula I_peak = I_rms × √2, where I_rms is the given RMS current of 35.0 A.

Step-by-step explanation:

To find the peak current produced by the generator, we first need to understand the relationship between the RMS (root mean square) values and peak values of current and voltage in AC circuits. The RMS value is the effective value that represents the DC equivalent of the AC current or voltage. The peak value is larger than the RMS value and is given by the formula:

I_peak = I_rms × √2

Given that the RMS current (I_rms) is 35.0 A, we can calculate the peak current (I_peak) as follows:

I_peak = 35.0 A × √2 ≈ 49.5 A

The peak current produced by the generator is approximately 49.5 A.

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