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An electron is to be accelerated in a uniform electric field having a strength of 1.20×10⁶

V/m. (a) What energy in keV is given to the electron if it is accelerated through 0.500 m ? keV (b) Over what distance (in km) would it have to be accelerated to increase its energy by 50.0Gev ?

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Final answer:

To accelerate an electron to gain 96 keV energy in a 1.20×10⁶ V/m electric field, it must travel through 0.500 m. To increase the electron's energy by 50.0 GeV, it would have to be accelerated over a distance of 26.04167 km.

Step-by-step explanation:

Calculating Electron Energy and Distance in an Electric Field

For an electron accelerated in a uniform electric field, the energy acquired by the electron can be calculated using the relationship between energy (eV), electric field (V/m), and distance (m). Given a field strength of 1.20×10⁶ V/m, the energy imparted to the electron as it travels through a distance of 0.500 m is found by using this formula:

Energy (eV) = Electric Field Strength (V/m) × Distance (m) × Charge of an electron (e)

The charge of an electron, e, is 1.60×10⁻¹⁹ C. Therefore, the energy gained in electronvolts (eV) is 1.20×10⁶ V/m × 0.500 m × 1.60×10⁻¹⁹ C which equals 96,000 eV, or 96 keV when converted to kilo-electron volts.

To find out over what distance it needs to be accelerated to increase its energy by 50.0 GeV, we again use the same relationship:

Distance (m) = Energy (eV) / (Electric Field Strength (V/m) × Charge of an electron (e))

Given that 50.0 GeV is equivalent to 5.0×10⁹ eV, and using the electric field strength of 1.20×10⁶ V/m, the distance needed would be 5.0×10⁹ eV / (1.20×10⁶ V/m × 1.60×10⁻¹⁹ C), which equals 26.04167 km.

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