Question

A square that has 29 cm long edges is centered on the x axis in a region where there exists a uniform electric field given by

E=(1.5kN/C)i
What is the electric flux of this electric field through the surface of a square if the normal to the surface is in the +x direction?

Answer 1

The electric flux through the surface of the square is 4.35 N m^2.

Step-by-step explanation:

The electric flux through the surface of a square can be calculated using the formula:

Electric flux = E x A x cos(theta)

Where E is the magnitude of the electric field, A is the area of the surface, and theta is the angle between the normal to the surface and the direction of the electric field.

In this case, the electric field is given by E = 1.5kN/C in the +x direction. The area of the square is 29 cm x 29 cm. Since the normal to the surface is in the +x direction, theta is 0 degrees. Plugging in these values into the formula, we get:

Electric flux = (1.5kN/C)(29 cm x 29 cm)(cos(0°))

Electric flux = 1.5kN x 29 cm² = 43.5kN cm² = 4.35N m²