Final answer:
The maximum speed of the block attached to the spring is 0.91 m/s.
Step-by-step explanation:
The acceleration of a block attached to a spring is given by the equation a = -0.350m/s² cos([2.42rad/s]t). To find the maximum speed of the block, we need to determine the amplitude of the velocity. The maximum velocity of a block in simple harmonic motion is equal to the product of the amplitude of acceleration and the period of oscillation. In this case, the amplitude of acceleration is 0.350 m/s² and the period is given by T = 2π/ω = 2π/2.42 = 2.60 s. Therefore, the maximum speed of the block is Vmax = (0.350 m/s²) * (2.60 s) = 0.91 m/s.