Question

A 2.0 mm diameter aluminum wire, 12 m long, carries a current of 800 mA. What is the strength of the electric field inside the wire?

Answer 1

The strength of the electric field inside the aluminum wire can be calculated using the formula E = I/(πr^2 ε₀), where E is the electric field, I is the current, r is the radius of the wire, and ε₀ is the permittivity of free space.

Step-by-step explanation:

The electric field inside the aluminum wire can be calculated using the formula:

E = I/(πr^2 ε₀)

where E is the electric field, I is the current, r is the radius of the wire, and ε₀ is the permittivity of free space.

First, we need to convert the diameter of the wire to radius and the current to amperes:

radius = 2.0 mm/2 = 1.0 mm = 0.001 m

I = 800 mA = 0.8 A

Next, we need to calculate the electric field using the given values:

E = 0.8 A / (π * (0.001 m)^2 * 8.854 x 10^-12 F/m)

Solving this equation will give us the strength of the electric field inside the wire.