Question

The loop is in a magnetic field 0.22 T whose direction is perpendicular to the plane of the loop. At t = 0, the loop has area A = 0.285 m2.Suppose the radius of the elastic loop increases at a constant rate, dr/dt = 3.45 cm/s . Determine the emf induced in the loop at t = 0 and at t = 1.00 s .

Answer 1

To determine the induced emf in the loop, we can use Faraday's Law of electromagnetic induction and the equation emf = -N(dΦ/dt), where N is the number of turns in the loop and dΦ/dt is the rate of change of magnetic flux.

Step-by-step explanation:

We can use Faraday's Law of electromagnetic induction to determine the induced emf (electromotive force) in the loop. The emf is given by the equation emf = -N(dΦ/dt), where N is the number of turns in the loop and dΦ/dt is the rate of change of magnetic flux through the loop.

For the given loop, the area A is constant, and the rate of change of magnetic flux is dΦ/dt = A(dB/dt). Plugging in the values, we have dΦ/dt = (0.285 m²)(3.45 cm/s) = 9.8325 x 10^-3 m²/s.

Using this value, we can calculate the emf at t = 0 and t = 1.00s using the equation emf = -N(dΦ/dt). The number of turns N is not given in the question.