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A straight 4.544 m wire carries a current of 0.405 A. If the wire is passed through a region of space with a uniform magnetic field of 0.426 T that is perpendicular to the flow of current, what is the magnitude of the force on the wire?

User Wolfuryo
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Final answer:

To calculate the magnitude of the force on the wire, we use the formula F=ILB*sin(θ), considering that the magnetic field is perpendicular to the current. The force is determined as 0.77932 N.

Step-by-step explanation:

The question asks for the magnitude of the force on a wire carrying a current and placed in a magnetic field. To find this force, we use the formula F = I * L * B * sin(θ), where F is the force, I is the current, L is the length of the wire within the magnetic field, B is the magnetic field strength, and θ is the angle between the wire and the direction of the magnetic field. Since it states that the magnetic field is perpendicular to the flow of current, θ is 90 degrees, and sin(θ) is 1. Plugging in the values provided: F = 0.405 A * 4.544 m * 0.426 T * 1. Therefore, the magnitude of the force on the wire is 0.77932 N.

User Veritas
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