Question

A 24 cm-diameter circular loop of wire has a resistance of 160Ω. It is initially in a 0.47 T magnetic field, with its plane perpendicular to B. but is removed from the field in 100ms. Calculate the electric energy dissipated in this process.

Answer 1

To calculate the electric energy dissipated in the process, we first need to find the induced emf in the loop. The induced emf can be calculated using Faraday's Law of electromagnetic induction. Once we have the induced emf, we can calculate the electric energy dissipated using the formula: E = I * V * t.

Step-by-step explanation:

To calculate the electric energy dissipated in the process, we first need to find the induced emf in the loop. The induced emf can be calculated using Faraday's Law of electromagnetic induction. Faraday's Law states that the emf induced in a loop of wire is equal to the rate of change of magnetic flux through the loop.

The magnetic flux through the loop can be calculated using the formula: Φ = B * A * cos(θ), where B is the magnetic field, A is the area of the loop, and θ is the angle between the magnetic field and the normal to the loop.

Once we have the induced emf, we can calculate the electric energy dissipated using the formula: E = I * V * t, where I is the current flowing through the loop, V is the voltage across the loop, and t is the time taken.