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The electric field of a sinusoidal electromagnetic wave obeys the equation E=−(365V/m)sin[(6.05×1015rad/s)t+(1.91×107rad/m)x]

What is the amplitude of the electric field of this wave?

User Trickbz
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Final answer:

The amplitude of the electric field for the given sinusoidal electromagnetic wave equation is 365 V/m, which is the coefficient of the sine function in the equation.

Step-by-step explanation:

The electric field of a sinusoidal electromagnetic wave is given by E = - (365 V/m) sin[(6.05 \u00d7 1015 rad/s)t + (1.91 \u00d7 107 rad/m)x]. The amplitude of the electric field is the maximum absolute value of E at any point in space or time. Since the amplitude is the coefficient of the sine function in the equation for E, the amplitude of the electric field for this wave is 365 V/m.

User Josiah Yoder
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