Question

In a double-slit experiment, d=14.4μm and the wavelength of the light is λ=600 nm. The intensity of light at the center of the central fringe is measured to be 12 μW/m². Determine the intensity at a point that is at an angle of 1.36∘ from the center of the central fringe (in μW/m²). (Use the ideal double slit intensity formula)

Answer 1

To determine the intensity at a point that is at an angle from the center of the central fringe in a double-slit experiment, you can use the ideal double slit intensity formula: I = I0 * cos^2(πdsinθ/λ), where I is the intensity at the point, I0 is the intensity at the center of the central fringe, d is the slit separation, θ is the angle from the center of the central fringe, and λ is the wavelength of the light.

Step-by-step explanation:

To determine the intensity at a point that is at an angle from the center of the central fringe in a double-slit experiment, we can use the ideal double slit intensity formula: I = I0 * cos^2(πdsinθ/λ), where I is the intensity at the point, I0 is the intensity at the center of the central fringe, d is the slit separation, θ is the angle from the center of the central fringe, and λ is the wavelength of the light.

Given that d = 14.4 μm, λ = 600 nm, I0 = 12 μW/m², and θ = 1.36°, we can substitute these values into the formula to calculate the intensity at the point:

θ = 1.36° * π/180 = 0.0237 rad

I = 12 μW/m² * cos^2((π * 14.4 μm * sin(0.0237 rad))/600 nm)

Finally, we can calculate the intensity using a calculator: