Final answer:
The jet takes 3.6 seconds to increase its velocity from 250 m/s to 430 m/s with a constant acceleration of 50 m/s squared.
Step-by-step explanation:
The student is asking about the time it takes for a jet to accelerate from an initial velocity (v0) of 250 m/s to a final velocity (v) of 430 m/s with a constant acceleration (a) of 50 m/s2. We can use the kinematic equation v = v0 + at to solve for the time (t).
Here is the step-by-step explanation:
- Start with the formula: v = v0 + at.
- Plug in the given values: 430 m/s = 250 m/s + (50 m/s2)t.
- Solve for t: t = (430 m/s - 250 m/s) / (50 m/s2).
- Calculate the result: t = 180 m/s divided by 50 m/s2 = 3.6 seconds.
Therefore, the jet takes 3.6 seconds to increase its velocity from 250 m/s to 430 m/s given a constant acceleration of 50 m/s2.