Question

If a particle with a 6.0 x 10-3 C charge traveling at 3.00 x 10⁴ m/s enters a magnetic field with a strength of 5.0 T in a direction parallel to the field (∅=0) what force is experienced by the particle? What is the flight path of the particle and why?

Answer 1

The force experienced by the particle is zero, and the flight path is a straight line.

Step-by-step explanation:

The force experienced by a charged particle moving in a magnetic field can be calculated using the formula F = qvBsin(∅), where F is the force, q is the charge of the particle, v is the velocity of the particle, B is the magnetic field strength, and ∅ is the angle between the velocity and the magnetic field direction.

In this case, the particle has a charge of 6.0 x 10-3 C, a velocity of 3.00 x 104 m/s, and enters a magnetic field with a strength of 5.0 T in a direction parallel to the field (∅ = 0). Since the angle is 0, the sin(0) term becomes 0, and the force experienced by the particle is 0 N.

The flight path of the particle will be a straight line, unaffected by the magnetic field, because the force experienced is zero.