Final answer:
The current supplied to an automobile starter motor with an equivalent resistance of 0.0490 ohms, connected to a 12.0 V battery with a 0.0110 ohms internal resistance, is calculated using Ohm's Law (V/R) and is determined to be 200 A.
Step-by-step explanation:
Calculating the Current to an Automobile Starter Motor
A student has asked about the current supplied to an automobile starter motor when it's connected to a 12.0 V battery with an internal resistance. The starter motor has an equivalent resistance of 0.0490 ohms (Ω), and the battery has an internal resistance of 0.0110 ohms. To find the current, we use Ohm's Law, which states that current (I) is equal to the voltage (V) divided by the total resistance (R).
The total resistance in the circuit is the sum of the motor's resistance and the battery's internal resistance:
Total Resistance = 0.0490 Ω + 0.0110 Ω = 0.0600 Ω
Applying Ohm's Law:
I = V / R = 12.0 V / 0.0600 Ω = 200 A
Therefore, the current that flows to the motor is 200 amperes (A).