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To determine vector D when vector B=(-i+2j), vector C=(3i-2j) where 3B-C+D=0 what is magnitude and direction of vector D

User Rlesias
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1 Answer

5 votes

Final answer:

To find the magnitude and direction of vector D, rearrange the given equation and substitute the values for vector B and vector C. Simplify the equation and isolate vector D. Calculate the magnitude of vector D using the formula and determine its direction using the arctan function.

Step-by-step explanation:

To determine the magnitude and direction of vector D, we can rearrange the equation 3B - C + D = 0 to solve for D. First, substitute the given values for vector B and vector C:

B = -i + 2j

C = 3i - 2j

Now, plug these values into the equation:

3(-i + 2j) - (3i - 2j) + D = 0

We can simplify the equation and isolate vector D:

-3i + 6j - 3i + 2j + D = 0

-6i + 8j + D = 0

D = 6i - 8j

The magnitude of vector D can be calculated using the formula:

|D| = sqrt((6)^2 + (-8)^2)

|D| = sqrt(36 + 64)

|D| = sqrt(100)

|D| = 10

The direction of vector D can be determined using the formula:

theta = arctan(Dy/Dx)

theta = arctan(-8/6)

theta = -53.13°

Therefore, the magnitude of vector D is 10 and its direction is -53.13°.-

User Renzo
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