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An automobile and a truck start from rest at the same instant, with the automobile initially at some distance behind the truck. The truck has a constant acceleration of 2.1 m/s², and the automobile an acceleration of 3.4 m/s². The automobile overtakes the truck after the truck has moved 40 m.

(a) Calculate the time taken by the automobile to overtake the truck.

User Pmt
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The time taken by the automobile to overtake the truck is t=6seconds.

The motion of the automobile and the truck can be analyzed using the kinematic equations of motion. Let's denote the distance covered by each vehicle as s and the time taken as t. The kinematic equation relates these variables as s=ut+ 1/2 at^2, where u is the initial velocity, a is the acceleration, and t is the time.

For the truck:

s truck​ = 1/2⋅2.1⋅t^2truck

​For the automobile:

s auto = 1/2⋅3.4⋅t^2 auto

​Given that the truck has moved 40 meters when the automobile overtakes it, we can set up an equation:

40= 1/2.2.1⋅t^2 truck

Solving for t truck gives t​ =4 seconds.

Now, since the automobile overtakes the truck, we can set up another equation for the distance covered by the automobile: s auto​=3.4⋅t^2 auto

​Given that the automobile overtakes the truck after the truck has moved 40 meters, we substitute t auto​ =t truck​+t overtake​ and s auto​=40+s truck. Solving for t overtake yields t overtake=6 seconds. Therefore, the automobile takes 6 seconds to overtake the truck.

User Mad Matts
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