Question

In horses black is dependent upon a dominant gene B and chestnut upon a recessive allele b.The trotting gait is due to a dominant gene T. The pacing gait is due to its recessive allele t. If a homozygous black pacer is mated to a homozygous chestnut.

Using a punnet square indicate the phenotypes that will appear in F2 generation if their progeny are intercrossed

Answer 1

In the F2 generation, you can expect black individuals with both pacing and trotting gaits, as well as chestnut trotters.

Coat color: B = black (dominant), b = chestnut (recessive)

Gait: T = trotting (dominant), t = pacing (recessive)

The homozygous black pacer is represented as bbtt (black coat color and pacing gait), and the homozygous chestnut is represented as BBTT (chestnut coat color and trotting gait).

When these two individuals are crossed, the genotype of the F1 generation will be BbTt (heterozygous black trotters). Now, let's see the possible phenotypes in the F2 generation when the F1 individuals are intercrossed.