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Rational Problem: Piper decided to walk to her friend Kenzie's house which is 10 km away.When she walked home, she was 3 km/h slower. The total walking time for the round trip was 7 hrs. How fast did she walk initially to her friend's house? (you will need to use the quadratic formula to solve this problem, but you will get a very nice whole number answer)​

User Yoyoma
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Final answer:

Piper's initial walking speed to Kenzie's house is 5 km/h, found by setting up an equation based on total distance and time, and then solving the resulting quadratic equation.

Step-by-step explanation:

To solve this rational problem, let's denote Piper's initial walking speed to Kenzie's house as x km/h. For the return trip, she walked 3 km/h slower, which would be (x - 3) km/h. The distance to Kenzie's house and back is the same, 10 km each way.

Using the formula time = distance / speed, we can write two equations for the time it takes to walk to Kenzie's house and back:

  • Time to Kenzie's: 10 km / x km/h
  • Time back home: 10 km / (x - 3) km/h

According to the problem, the total walking time for the round trip was 7 hours:

10/x + 10/(x - 3) = 7

To solve this equation, we need to clear the denominators by multiplying through by the common denominator, x(x - 3), which gives us:

10(x - 3) + 10x = 7x(x - 3)

This simplifies to:

10x - 30 + 10x = 7x^2 - 21x

Combining like terms, we get a quadratic equation:

7x^2 - 41x + 30 = 0

Applying the quadratic formula x = [-b ± √(b^2 - 4ac)] / (2a) (where a=7, b=-41, and c=30) yields two potential solutions for x. Only one of these will make sense in the context of the problem (a positive speed that fits within the 7-hour time frame).

After calculating, we find that the reasonable, whole number solution for Piper's initial walking speed to Kenzie's house is 5 km/h.

User Carol Ward
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