Final answer:
2dm^3 of 0.5M sulfuric acid, you would need to dilute 0.5dm^3 of 2M sulfuric acid with water. 2M sulfuric acid that must be diluted with water to produce 2dm3 of 0.5M sulfuric acid, we can use the formula for dilution: C1V1 = C2V2. Where C1 and V1 are the concentration and volume of the initial solution.
Step-by-step explanation:
To calculate the volume of 2M sulfuric acid that must be diluted with water to produce 2dm3 of 0.5M sulfuric acid, we can use the formula for dilution: C1V1 = C2V2. Where C1 and V1 are the concentration and volume of the initial solution, and C2 and V2 are the concentration and volume of the final solution.
Plugging in the values, we get:
2M x V1 = 0.5M x 2dm3
V1 = (0.5M x 2dm3) / 2M
V1 = 0.5dm3
2dm^3 of 0.5M sulfuric acid, you would need to dilute 0.5dm^3 of 2M sulfuric acid with water. 2M sulfuric acid that must be diluted with water to produce 2dm3 of 0.5M sulfuric acid, we can use the formula for dilution: C1V1 = C2V2. Where C1 and V1 are the concentration and volume of the initial solution, and C2 and V2 are the concentration and volume of the final solution. you would need to dilute 0.5dm3 of 2M sulfuric acid with water to produce 2dm3 of 0.5M sulfuric acid.