The inverse of T(t)=120 + (380)e⁻⁰.⁵⁶⁷ᵗ is t(T) = -ln(T - 120) / 0.567.
The inverse of T(t)=120 + (380)e⁻⁰.⁵⁶⁷ᵗ can be represented as t(T), where t is the time and T is the temperature.
To find the inverse, we need to isolate t in the equation.
T(t) = 120 + (380)e⁻⁰.⁵⁶⁷ᵗ
T - 120 = (380)e⁻⁰.⁵⁶⁷ᵗ
ln(T - 120) = -0.567t
t = -ln(T - 120) / 0.567
Therefore, the inverse of T(t)=120 + (380)e⁻⁰.⁵⁶⁷ᵗ is t(T) = -ln(T - 120) / 0.567.