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An electron with velocity v=8.60×10⁴m/sx is traveling in a region of space with electric field E=2200 N/Cx+5600 N/Cz and magnetic field B=0.140 Tz. Find the net electromagnetic force on the electron.

User Rien
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Final answer:

The net electromagnetic force on the electron is 3.52x10^-15 N i^ + 0.1936x10^-10 N m/s j^.

Step-by-step explanation:

The net electromagnetic force on an electron can be calculated by converting its velocity and the electric and magnetic fields into vectors and using the formula F = q(E + v x B), where F is the force, q is the charge of the electron, E is the electric field vector, v is the velocity vector, and B is the magnetic field vector.

In this case, the velocity vector of the electron is given as v = 8.60x10^4 m/s i^, the electric field vector is given as E = 2200 N/C i^ + 5600 N/C k^, and the magnetic field vector is given as B = 0.140 T k^.

Plugging these values into the formula, we have:

F = q(E + v x B)

= (1.6x10^-19 C)(2200 N/C i^ + 5600 N/C k^ + (8.60x10^4 m/s i^ x 0.140 T k^)

= (1.6x10^-19 C)(2200 N/C i^ + 0.140x8.60x10^4 N/C m/s j^)

= (1.6x10^-19 C)(2200 N/C i^ + 0.140x8.60x10^4 N/C m/s j^)

= (3.52x10^-15 N i^ + 0.1936x10^-10 N m/s j^)

Therefore, the net electromagnetic force on the electron is 3.52x10^-15 N i^ + 0.1936x10^-10 N m/s j^.

User Bithavoc
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