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An isolated monatomic gas, with mass of 0.0150kg is maintained at 1.50x10⁵Pa and T=350.0K. The average mass of the gas particle is 3.35x10⁻²⁶ kg. Find the mass density of the gas.

User Nkuhta
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Final answer:

The mass density of the gas is 4.90 kg/m³.

Step-by-step explanation:

The mass density of a gas can be calculated using the formula:

ρ = m/V

where ρ is the mass density, m is the mass of the gas, and V is the volume of the gas.

In this case, the mass of the gas is given as 0.0150 kg. To find the volume of the gas, we can use the ideal gas law:

pV = nRT

Rearranging the formula, we can solve for V:

V = nRT/p

where p is the pressure of the gas, T is the temperature, and n is the number of moles of the gas.

Substituting the given values into the equation and solving for V, we find:

V = (0.0150 kg)(8.314 J/(mol·K))(350.0 K)/(1.50 × 10^5 Pa)

Simplifying, we get V ≈ 3.06 × 10^-3 m³

Finally, substituting the values of m and V into the mass density formula, we can calculate:

ρ = (0.0150 kg)/(3.06 × 10^-3 m³)

ρ ≈ 4.90 kg/m³

User Wrench
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