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The pressure of oil in a reservoir tends to drop with time. The change is modeled by f(t)=1.06t³ -24.6t²+180t for t (in years ) in the interval 0,15. What was the change after 2 years?

User Tmcc
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Final answer:

The change in pressure of the oil in a reservoir after 2 years is determined by plugging in t = 2 into the model f(t) = 1.06t³ - 24.6t² +180t and calculating the result.

Step-by-step explanation:

The student is asking about how to calculate the change in pressure of oil in a reservoir over a period of 2 years using the given model f(t) = 1.06t³ - 24.6t² + 180t, where t is the time in years. To find the change after 2 years, we simply plug t = 2 into the model:

f(2) = 1.06(2)³ - 24.6(2)² + 180(2)

After calculating, we find the change in pressure after 2 years. It's essential to understand that this mathematical model is an application of calculus or algebra in predicting physical phenomena such as the behavior of pressure over time within an oil reservoir.

User Tavares
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