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A pool ball leaves a 0.80-meterhigh table with an initial horizontal velocity of 5.4(m)/(s). Calculate the time required for the pool ball to fall to the ground.

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Final answer:

The time required for the pool ball to fall to the ground is 0.40 seconds.

Step-by-step explanation:

To calculate the time required for the pool ball to fall to the ground, we can use the equation:

h = (1/2)gt^2

where:

  • h is the initial height, which is 0.80 m
  • g is the acceleration due to gravity, which is approximately 9.8 m/s²
  • t is the time

First, let's rearrange the equation:

t = sqrt(2h/g)

Substituting the given values:

t = sqrt(2*0.80/9.8) = 0.40 s

Therefore, the time required for the pool ball to fall to the ground is 0.40 seconds.

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