Final answer:
The magnitude of the electrical force of attraction between two charges can be calculated using Coulomb's law. In this case, the charges are -3.0 C and +3.0 C, and the distance between them is 25 km. Using Coulomb's law formula, the magnitude of the force is found to be 2.16 x 10^5 N.
Step-by-step explanation:
The magnitude of the electrical force of attraction between two charges can be calculated using Coulomb's law.
Coulomb's law states that the magnitude of the force between two charges is directly proportional to the product of the magnitudes of the charges and inversely proportional to the square of the distance between them.
In this case, the charges are -3.0 C and +3.0 C, and the distance between them is 25 km (which is equivalent to 25,000 m).
Using Coulomb's law formula, we can calculate the magnitude of the force:
F = k * (|q1| * |q2|) / r^2
Where k is the electrostatic constant (k = 9 x 10^9 N m^2/C^2), |q1| and |q2| are the magnitudes of the charges, and r is the distance between the charges.
Plugging in the values, we get:
F = (9 x 10^9 N m^2/C^2) * (3.0 C * 3.0 C) / (25,000 m)^2
Simplifying the equation gives us:
F = 2.16 x 10^5 N