Question

A 24.30 V battery is used to supply current to a 18kΩ resistor. Assume the voltage drop across any wires used for connections is negligible. What is the current (in mA ) through the resistor?

Answer 1

The current through an 18kΩ resistor connected to a 24.30 V battery is 1.35 mA.

Step-by-step explanation:

To calculate the current through an 18kΩ resistor when a 24.30 V battery is connected, we use Ohm’s Law, which is represented by the equation V = IR, where V is the voltage, I is the current, and R is the resistance.

In this case, the voltage V is 24.30 V, and the resistance R is 18kΩ (or 18000 Ω). So the current I can be found using the formula:

I = V / R = 24.30 V / 18000 Ω

Calculating this gives us:

I = 0.00135 A, which can also be written as 1.35 mA (since 1 A = 1000 mA). Therefore, the current through the resistor is 1.35 mA.