Final answer:
The acceleration of the electron in the given electric field is -1.81 x 10^17 m/s^2.
Step-by-step explanation:
The acceleration of an electron in a constant electric field can be found using the formula:
acceleration = electric field strength / electron charge
Given that the magnitude of the electric field is 290 N/C and the charge of an electron is -1.60 × 10^-19 C, we can substitute these values into the formula to calculate the acceleration:
acceleration = 290 N/C / (-1.60 × 10^-19 C) = -1.81 x 10^17 m/s^2.
Therefore, the acceleration of the electron is -1.81 x 10^17 m/s^2.