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If one sound has the intensity of 2.3x 10⁻⁶ watts per square meter [(W)/(m²)], anc a second sound has an intensity of 6.5x 10⁻⁶(W)/(m²), what is the difference between the intensities of the two sounds?

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Final answer:

The difference between the intensities of the two sounds with intensities 2.3 x 10⁻⁶ W/m² and 6.5 x 10⁻⁶ W/m² is 4.2 x 10⁻⁶ watts per meter squared.

Step-by-step explanation:

The question asks about calculating the difference between the intensities of two sounds, with intensities given in watts per meter squared (W/m²). The difference between the intensities of the first sound (2.3 x 10⁻⁶ W/m²) and the second sound (6.5 x 10⁻⁶ W/m²) can be found by simply subtracting the intensity of the first sound from the intensity of the second sound:

Intensity difference = 6.5 x 10⁻⁶ W/m² - 2.3 x 10⁻⁶ W/m²

Intensity difference = 4.2 x 10⁻⁶ W/m²

Therefore, the difference between the intensities of the two sounds is 4.2 x 10⁻⁶ watts per meter squared.

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