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A uniform test tube loaded with 100 lead shots floats upright in water with 8cm of its length is immersed. What length is immersed when floats in glycerol? (Density of glycerol is 1.3(g)/(c)m³ )

User Ayoub K
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1 Answer

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Final answer:

To find the length of the test tube immersed in glycerol, we can use Archimedes' principle and the density of glycerol. By finding the volume of the lead shots submerged in water and using the density of glycerol, we can calculate the length of the test tube immersed in glycerol.

Step-by-step explanation:

To determine the length of the test tube immersed in glycerol, we can use Archimedes' principle which states that the buoyant force on an object submerged in a fluid is equal to the weight of the fluid displaced.

First, we need to find the volume of the lead shots that are submerged in water. Since 8cm of the test tube is immersed, the volume of the lead shots submerged is the cross-sectional area of the test tube multiplied by 8cm.

Next, we can use the density of glycerol (1.3 g/cm³) to find the length of the test tube immersed in glycerol. The density of glycerol can be calculated by dividing the weight of the glycerol by the volume of the glycerol displaced by the test tube. From there, we can find the length of the test tube immersed in glycerol by dividing the volume of the lead shots submerged in water by the cross-sectional area of the test tube.

User Nefzen
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