Question

What is the velocity of a beam of electrons that goes undellected when moving perpendicular to an electric and magnobie fields. E and B are also perpendicular to each other anc have magnitudes 4100 V/m and 8.9×10−³ T, respectively.

Answer 1

The velocity of the beam of electrons that goes undellected can be calculated using the formula v = E/B, with the given values of electric and magnetic fields. The velocity is approximately 460.67 m/s.

Step-by-step explanation:

The velocity of a beam of electrons that goes undellected when moving perpendicular to electric and magnetic fields can be calculated using the formula v = E/B, where v is the velocity, E is the electric field, and B is the magnetic field. In this case, the electric field has a magnitude of 4100 V/m and the magnetic field has a magnitude of 8.9×10⁻³ T. Plugging these values into the formula, we get v = 4100/8.9×10⁻³, which is approximately 460.67 m/s.