Question

A solid disk (think of it as a really thin cylinder) of mass

0.171 kg and radius 0.148 m experiences a net torque of 0.0290 N*m.
What is the magnitude of the angular acceleration of the disk?

Answer 1

The magnitude of the angular acceleration of the disk is 19.66 rad/s^2.

Step-by-step explanation:

To find the angular acceleration of the solid disk, we can use the equation:

τ = Iα

Where τ is the net torque, I is the moment of inertia, and α is the angular acceleration.

We are given the net torque = 0.0290 N*m, the mass of the disk = 0.171 kg, and the radius of the disk = 0.148 m.

The moment of inertia for a solid disk is given by the formula I = (1/2) * m * r^2. Plugging in the values, we get:

I = (1/2) * 0.171 kg * (0.148 m)^2 = 0.001475 kg * m^2

Now we can solve for α:

0.0290 N*m = 0.001475 kg * m^2 * α

α = 0.0290 N*m / 0.001475 kg * m^2 = 19.66 rad/s^2