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Consider the joint probability density function fx,y(x, y) = 12x³y, 0

User Jdelator
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Final answer:

The probability of an event happening between 0 and 12 for a continuous probability function with f(x) = 12 is 144.

Step-by-step explanation:

For a continuous probability function, the probability of an event happening between two values is equal to the area between the function and the x-axis within that interval.

In this case, we have f(x) = 12, which is a constant function. The area under a constant function within any interval is equal to the length of the interval multiplied by the value of the function.

Since the function is restricted to 0 ≤ x ≤ 12, the probability of the event happening between 0 and 12 is P(0 < x < 12) = 12 * 12 = 144.

User Michael Broschat
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