Question

From a sample of 100 students, the mean number of time streaming Netflix, Prime, Crave etc. per week is 15.5 hours with a standard deviation 6.5 hours.

Using an 90% confidence level, what is the t-value?
(a).1.280
(b).1.29
(c).1.645
(d).1.660

Answer 1

The correct t-value for constructing a 90% confidence interval for a sample of 100 students is approximately 1.66, corresponding to option (d).

Step-by-step explanation:

The student is asking to identify the correct t-value required to calculate a 90% confidence interval for estimating the mean streaming time of a sample of students. Since the sample size is 100, which is large, one could consider using the Z-distribution; however, since we are using the sample standard deviation, the appropriate distribution is the t-distribution. To find the t-value for a 90% confidence level with 99 degrees of freedom (n - 1 = 100 - 1 = 99), we can use a t-distribution table or appropriate statistical software. The closest tabulated value for a 90% confidence level typically yields a t-value around 1.66 for large degrees of freedom, which corresponds to option (d).